If the zeroes of the polynomial p(x) = 2×2 – 7x + 6 is are α and β, then the then the value of 1/α + 1/β :

If the zeroes of the polynomial p(x) = 2x² – 7x + 6 is are α and β, then the then the value of 1/α + 1/β :
(A) 7/2
(C) – 7/6
(B) 6/7
(D) 7/6

Solution : Correct answer is : (D) 7/6

For a quadratic $ax^2 + bx + c$

Find $\frac{1}{\alpha} + \frac{1}{\beta}$

Correct answer is : (D) 7/6.